1958 Tybee Island mid-air collision
Startread by S Whistler · recorded April 25, 2012 · 0:06:05 · 4.5 MB
The Tybee Island mid-air collision was an incident on February 5, 1958, in which the United States Air Force lost a 7,600-pound (3,400 kg) Mark 15 nuclear bomb in the waters of Tybee Island near Savannah, Georgia, United States. During a night practice exercise, an F-86 fighter plane collided with the B-47 bomber carrying the large weapon. The bomb was jettisoned to help prevent a crash and explosion. After several unsuccessful searches, the weapon was declared lost in Wassaw Sound off the shores of Tybee Island.
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